Question

I’m willing to give lots of points for this question ;)

Answer 1

Answer:

$Cu^{2+} + 2e^{-} --> Cu^{0} ||reduction||cathode$

$2O^{-2} -4e^{-}-->O_{2}^{0}|| oxidation|| anode$

$Li^{+} +1e^{-}--> Li^{0} || reduction|| cathode$

$2H^{+} + 2e^{-}-->H_{2}^{0}|| reduction||cathode$

$Mg^{2+} +2e^{-} --> Mg^{0}|| reduction|| catode$

$Al^{3+}+3e^{-} --> Al^{0}||reduction||cathode$

Metal ions have positive charges, and are attracted to the negative electrode (the cathode)  and are reduced during electrolysis.

Non-metal ions have negative charges, and are attracted to the positive electrode (the anode)  and are oxidized during electrolysis.