Question

If a rock falls from a height of 60 meters on Earth, the height H (in meters) after x seconds is approximately H(x) = 60 - 4.9x2. When does the rock strike the ground? Round to the nearest hundredth, if necessary.

Answer 1

using the x = Vt + 0.5 a*t^2 equation,

plug in the values to get 0 = -4.9t^2 + 60.

solve for t to get 3.5

Answer 2

The rock strikes the ground after 3.5 seconds.

What is an equation?

"It is a statement which consists of equal symbol between two mathematical expressions."

For given example,

If a rock falls from a height of 60 meters on Earth, the height H (in meters) after x seconds is given by an equation H(x) = 60 - 4.9x²

We need to find the time 'x' at which the rock strikes the ground.

When rock strikes the ground then height H = 0 meter

An equation H(x) = 60 - 4.9x² becomes,

⇒ 0 = 60 - 4.9x²

⇒ 4.9x² = 60

⇒ x² = 12.2448

⇒ x = 3.5 seconds

Therefore, the rock strikes the ground after 3.5 seconds.

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