Question

A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck travel in the given time?

Answer 1

vf = vi + at
vf = 6 + (2)(12)
vf = 6 + 24
vf = 30

2as = vf² - vi²
2(2)s = (30)² - (6)²
4s = 900 - 36
4s = 864
s = 864/4
s = 216
d = 216

Answer 2

Answer:

Distance, d = 216 meters

Explanation:

Given that,

Initial velocity of the truck, u = 6 m/s

Acceleration of the truck, $a=2\ m/s^2$

Time taken, t = 12 seconds

Let d is the distance travelled by the truck in the given time. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2$

$d=6(12)+\dfrac{1}{2}\times 2\times (12)^2$

d = 216 meters

So, the distance covered by the truck during this time is 216 meters. Hence, this is the required solution.