Question

Make perfect square
V^2 + 8v +

Answer 1

If you're asking for the final term, the solution is to take b(from ax^2+bx+c), half it, and then square it. So in this case, b is 8.
8/2=4
4^2=16
So:
v^2+8v+16
If you factor it, it becomes (v+4)^2, which shows that its a perfect square.