Question

Simplify $\frac{x^3-x+1}{ \sqrt{x} }$

Answer 1

Divide each term by $\sqrt{x}$ to get $x^{2} \sqrt{x} - \sqrt{x} + \frac{ \sqrt{x} }{x}$

Answer 2

$\frac{x^{3} - x + 1}{\sqrt{x}} = \frac{x^{3} - x + 1}{\sqrt{x}} \times \frac{\sqrt{x}}{\sqrt{x}} = \frac{(x^{3} - x + 1)\sqrt{x}}{x} = \frac{x^{3}\sqrt{x} - x\sqrt{x} + \sqrt{x}}{x} = x^{2}\sqrt{x} - \sqrt{x} + \frac{\sqrt{x}}{x}$