tammy0775
tammy0775
28-08-2016
Mathematics
contestada
f(x)= sqare root x-5. find f^1
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dalendrk
dalendrk
28-08-2016
[tex]f(x)=\sqrt{x-5}\\The\ domain\ D_f=x-5\geq0\to x\geq5\\\\y=\sqrt{x-5}\ \ \ \ |square\ both\ sides\\\\y^2=x-5\ \ \ \ \ |add\ 5\ to\ both\ sides\\\\x=y^2+5\\\\Answer:\boxed{f^{-1}(x)=x^2+5\ for\ x\in[0;\ \infty)}[/tex]
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