Answer: The percentage by mass of carbon in the given compound is 45.8 %
Explanation:
We are given a chemical compound having chemical formula [tex]C_{10}H_{14}N_2[/tex]
To calculate the percentage composition of an element in a compound, we use the equation:
[tex]\%\text{ composition}=\frac{\text{Mass of carbon element}}{\text{Mass of compound}}\times 100[/tex]
In 1 mole of given compound, 10 moles of carbon atoms are there.
Mass of [tex]C_{10}H_{14}N_2= [(10\times 12)+(14 \times 1)+(2\times 14)]=262g/mol[/tex]
Mass of carbon element = [tex][10\times 12]=120g/mol[/tex]
Putting values in above equation, we get:
[tex]\%\text{ composition of carbon}=\frac{120}{262}\times 100=45.8\%[/tex]
Hence, percentage of carbon in given compound is 45.8 %.
