m^(- 5) = 1/35 → you know that: x^(- a) = 1/x^(+ a) = 1/x^a
1/m^5 = 1/35 → you take the inverse
m^5 = 35
[m^5]^(1/5) = 35^(1/5) → recall: (x^a)^b = x^(ab)
m^[5 * (1/5)] = 35^(1/5)
m^[1)] = 35^(1/5)
m = 35^(1/5)
The scientific notation is a number between 1 and 9 with few numbers after coma (point) completed by a power 10.
= [1.4 * 10^(3)] * [2.5 * 10^(- 6)] → you remove the brackets
= 1.4 * 10^(3) * 2.5 * 10^(- 6) → you order
= 1.4 * 2.5 * 10^(3) * 10^(- 6) → you make the multiplication
= 3.5 * 10^(3) * 10^(- 6) → recall: (x^a) * (x^b) = x^(a + b)
= 3.5 * 10^(3 - 6)
= 3.5 * 10^(- 3) ← answer C
