Question

Two positive integers are 3 units apart on a number line. Their product is 108.

Solve for m, the greater integer, using which of the equation below?

m(m – 3) = 108

A. m(m + 3) = 108
B. (m + 3)(m – 3) = 108
C. (m – 12)(m – 9) = 108

Answer 1

The first integer as given in the question = m
Then
The second integer as described in the question = m + 3
Then the equation will be
m(m + 3) = 108
The correct option is option "A".
Now let us solve for "m"
m^2 + 3m - 108 = 0
m^2 + 12m - 9m - 108 = 0
m(m + 12) - 9(m + 12) = 0
(m + 12)(m - 9) =0
So the value of "m" is -12 and 9.

Answer 2

Answer:

The answer is A on edge 2020.

Explanation: