Respuesta :
f(1) = 100
f(2) = 100 - 8 = 92
f(3) = 92 - 8 = 84
f(4) = 84 - 8 = 76
f(5) = 76 - 8 = 68
f(6) = 68 - 8 = 60
Arithmetic Serieshaving a1=100
common difference d=-8
The nth term=a +(n - 1)d.
When n = 6
f(6) = 100 + (6 - 1)(-8)
= 100 - 40
= 60.
f(2) = 100 - 8 = 92
f(3) = 92 - 8 = 84
f(4) = 84 - 8 = 76
f(5) = 76 - 8 = 68
f(6) = 68 - 8 = 60
Arithmetic Serieshaving a1=100
common difference d=-8
The nth term=a +(n - 1)d.
When n = 6
f(6) = 100 + (6 - 1)(-8)
= 100 - 40
= 60.