The first quartile of a data set is 32, and the third quartile is 52. One of these values in the data set is an outlier. Which of the following is this?
A. 23
B. 3
C. 63
D. 83

Respuesta :

As we know that the formula of outlier is 
IQR = Q3 - Q1
 = 52 - 32
 = 20
52 + 1.5(20) = 82...
 so anything above 82 is an outlier
now
32 - 1.5(20) = 2.
..anything below 2 is an outlier

so...the 83 is outlier
so correct option is D 
hope it helps

Answer:  D. 83

Explanation:

Given: The first quartile of a data set is [tex]Q_1=32[/tex], and the third quartile is  [tex]Q_2=52[/tex].

The formula of to calculate the interquartile range is :-

[tex]IQR= Q_3 - Q_1= 52-32= 20[/tex]

 The lower limit of interval for the data having no outlier :-

[tex]Q_1-1.5(IQR)=32-1.5(20) = 2[/tex]

The upper limit of interval for the data having no outlier:-

[tex]Q_3+1.5(IQR)=52+1.5(20) = 82[/tex]

Since 83 is the value which lies outside the interval or greater than the upper limit.

Therefore, outlier for the data = 83.

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