Respuesta :
As we know that the formula of outlier is
IQR = Q3 - Q1
= 52 - 32
= 20
52 + 1.5(20) = 82...
so anything above 82 is an outlier
now
32 - 1.5(20) = 2.
..anything below 2 is an outlier
so...the 83 is outlier
so correct option is D
hope it helps
IQR = Q3 - Q1
= 52 - 32
= 20
52 + 1.5(20) = 82...
so anything above 82 is an outlier
now
32 - 1.5(20) = 2.
..anything below 2 is an outlier
so...the 83 is outlier
so correct option is D
hope it helps
Answer: D. 83
Explanation:
Given: The first quartile of a data set is [tex]Q_1=32[/tex], and the third quartile is [tex]Q_2=52[/tex].
The formula of to calculate the interquartile range is :-
[tex]IQR= Q_3 - Q_1= 52-32= 20[/tex]
The lower limit of interval for the data having no outlier :-
[tex]Q_1-1.5(IQR)=32-1.5(20) = 2[/tex]
The upper limit of interval for the data having no outlier:-
[tex]Q_3+1.5(IQR)=52+1.5(20) = 82[/tex]
Since 83 is the value which lies outside the interval or greater than the upper limit.
Therefore, outlier for the data = 83.