Respuesta :
Each layer contains the square of the layer number.
So,
Let's figure out :
1 squared = 1
2 squared = 4
3 squared = 9
4 squared = 16
5 squared = 25
6 squared = 36
Hence,
The total number of oranges in the pile = 1+4+9+16+25+36
= 91 oranges
D. 91
So,
Let's figure out :
1 squared = 1
2 squared = 4
3 squared = 9
4 squared = 16
5 squared = 25
6 squared = 36
Hence,
The total number of oranges in the pile = 1+4+9+16+25+36
= 91 oranges
D. 91
The answer is 91.
The question is based on on a mathematical topic called ''Geometry'', and is simply asking for the total number of the oranges in the four-sided pyramid.
Further Explanation
In geometry, a pyramid is a polyhedron that is constructed when the polygonal base is connected to an iconic surface. The base edge and apex form a triangle that is called a lateral face. A pyramid can also be with an n-sided base that has n + 1 vertices, n + 1 faces, and 2n edges.
But the first thing to do is to get the number of oranges in each phases of the four-sided pyramid. To do this, we square the root the numbers of the vertices.
1 squared = 1 [for the first phase of the pyramid]
2 squared =4 [we got 4 as our answer for the second layer of the pyramid]
3 squared = 9 [9, for the third phase of pyramid]
4 squared = 16
5 squared = 25
6 squared = 36 [and 36 is the last in the pyramid]
The addition of the total oranges in each phase of the six layers is 91.
The total number of oranges in the pile = 1+4+9+16+25+36=91
KEYWORDS:
- polygon
- geometry
- four-sided pyramid
- polyhedron
- triangle