Answer:
C.I = 0.108 ± 0.022
Step-by-step explanation:
In this case, we are given a symmetric confidence interval, and the sample proportion p', is derived by finding the average of the two values.
Therefore, the sample proportion will be:
[tex] p' = \frac{0.086 + 0.130}{2} [/tex]
[tex] = \frac{0.216}{2} [/tex]
= 0.108
p' = 0.108
To find the margin of error, we have:
M.E = ½ * length of confidence interval
Where length of confidence interval = 0.130 - 0.086
= 0.044
Therefore,
[tex] M.E = \frac{1}{2} * 0.044 = 0.022 [/tex]
Margin of error = 0.022
The confidence interval is expressed as:
p' ± M.E
= 0.108 ± 0.022