Respuesta :

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

   [tex]A_1 = 67.58 \ in^2[/tex]

2

   [tex]A_2 =415.4 \ ft^2[/tex]

3

   [tex]A_3 = 8.48 \ cm^2[/tex]

4

  [tex]A_4 = 480.38 \ m^2[/tex]

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

         [tex]A = \frac{\theta}{360} * \pi r^2[/tex]

Now at [tex]r_1 = 11 in[/tex] and  [tex]\theta_1 = 64^o[/tex]

       [tex]A_1 = \frac{64}{360} * 3.142 * 11^2[/tex]

       [tex]A_1 = 67.58 \ in^2[/tex]

Now at  [tex]r_2 = 20 ft[/tex] in and  [tex]\theta_2 = 119 ^o[/tex]

       [tex]A_2 = \frac{119}{360} * 3.142 * 20^2[/tex]

       [tex]A_2 =415.4 \ ft^2[/tex]

Now at  [tex]r_3 = 6.5 cm[/tex]   and  [tex]\theta_3 = 23 ^o[/tex]

     [tex]A_3 = \frac{23}{360} * 3.142 * 6.5 ^2[/tex]

      [tex]A_3 = 8.48 \ cm^2[/tex]

Now at  [tex]r_4 = 14.2 m[/tex]   and  [tex]\theta_4 = 360 -87 = 273 ^o[/tex]

         [tex]A_4 = \frac{273}{360} * 3.142 * 14.2^2[/tex]

          [tex]A_4 = 480.38 \ m^2[/tex]

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