Complete Question
The complete question is shown on the first uploaded image
Answer:
1
[tex]A_1 = 67.58 \ in^2[/tex]
2
[tex]A_2 =415.4 \ ft^2[/tex]
3
[tex]A_3 = 8.48 \ cm^2[/tex]
4
[tex]A_4 = 480.38 \ m^2[/tex]
Step-by-step explanation:
Generally the area of a sector is mathematically represented as
[tex]A = \frac{\theta}{360} * \pi r^2[/tex]
Now at [tex]r_1 = 11 in[/tex] and [tex]\theta_1 = 64^o[/tex]
[tex]A_1 = \frac{64}{360} * 3.142 * 11^2[/tex]
[tex]A_1 = 67.58 \ in^2[/tex]
Now at [tex]r_2 = 20 ft[/tex] in and [tex]\theta_2 = 119 ^o[/tex]
[tex]A_2 = \frac{119}{360} * 3.142 * 20^2[/tex]
[tex]A_2 =415.4 \ ft^2[/tex]
Now at [tex]r_3 = 6.5 cm[/tex] and [tex]\theta_3 = 23 ^o[/tex]
[tex]A_3 = \frac{23}{360} * 3.142 * 6.5 ^2[/tex]
[tex]A_3 = 8.48 \ cm^2[/tex]
Now at [tex]r_4 = 14.2 m[/tex] and [tex]\theta_4 = 360 -87 = 273 ^o[/tex]
[tex]A_4 = \frac{273}{360} * 3.142 * 14.2^2[/tex]
[tex]A_4 = 480.38 \ m^2[/tex]