Answer:
75.44 Square Inches
Step-by-step explanation:
The diagram of the problem is produced and attached.
To determine the area of the cleaned sector:
Let the radius of the larger sector be R
Let the radius of the smaller sector be r
Area of the larger sector [tex]=\frac{\theta}{360}X\pi R^2[/tex]
Area of the smaller sector [tex]=\frac{\theta}{360}X\pi r^2[/tex]
Area of shaded part =Area of the larger sector-Area of the smaller sector
[tex]=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)[/tex]
From the diagram, R=10 Inch, r=10-7=3 Inch, [tex]\theta=95^\circ[/tex]
Therefore, Area of the sector cleaned
[tex]=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches[/tex]