Question

A sample of neon gas occupies a volume of 2.8 L at a temp. of 55◦C. The sample is cooled to 30. ◦C, what is the new volume in mL?

a: 2,600 mL
b: 15.4 mL
c: 15 mL
d: 1.5 L

Answer 1

Answer:

The new volume is 2580 mL.

Explanation:

Charles law gives the relationship between volume and temperature of the gas. According to this law, volume of gas is directly proportional to temperature, pressure remains constant.

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Here,

$V_1=2.8\ L\\\\T_1=55^{\circ} C=328.15\ K\\\\T_2=30^{\circ} C=303.15\ K$

We need to find V₂. So,

$V_2=\dfrac{V_1T_2}{T_1}$

$V_2=\dfrac{2.8\times 303.15}{328.15}\\\\V_2=2.58\ L$

2.58 L = 2580 mL

So, the new volume is 2580 mL.