Question

What is the following sum?

RootIndex 3 StartRoot 125 x Superscript 10 Baseline y Superscript 13 Baseline EndRoot + RootIndex 3 StartRoot 27 x Superscript 10 Baseline y Superscript 13 Baseline EndRoot

Answer 1

Answer:

The sum will give $8x^{10} y^{13}$

Step-by-step explanation:

Given the indicinal equation as shown;

$\sqrt[3]{125}x^{10} y^{13} +\sqrt[3]{27}x^{10} y^{13}$

To find the sum, we need to find the cube roots of the given number first as shown:

$5x^{10} y^{13} +3x^{10} y^{13}$

The we add their coefficient together since they have the same incidinal function attached to them i.e $x^{10} y^{13}$

The sum will give $8x^{10} y^{13}$.

Answer 2

The sum of the equation is $\rm 8 x^{10 }y^{13 }$.

Given that,

Equation; $\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }$

We have to find,

The sum of the equation.

According to the question,

Equation; $\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }$

To determine the sum of the equation following all the steps given below.

• Step1; Convert the numbers 125 and 27 into the cubes,

                    $= \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }\\\\= \sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }$

• Step2; Add their coefficient together since they have the same incidental function attached to them,

                   $\rm =\sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }\\\\=5 x^{10 }y^{13 }+ 3 x^{10 }y^{13 }\\\\= 8 x^{10 }y^{13 }$

Hence, The sum of the equation is $\rm 8 x^{10 }y^{13 }$.

For more details refer to the link given below.

https://brainly.com/question/18431073