What is the following sum?

RootIndex 3 StartRoot 125 x Superscript 10 Baseline y Superscript 13 Baseline EndRoot + RootIndex 3 StartRoot 27 x Superscript 10 Baseline y Superscript 13 Baseline EndRoot

Respuesta :

Answer:

The sum will give [tex]8x^{10} y^{13}[/tex]

Step-by-step explanation:

Given the indicinal equation as shown;

[tex]\sqrt[3]{125}x^{10} y^{13} +\sqrt[3]{27}x^{10} y^{13}[/tex]

To find the sum, we need to find the cube roots of the given number first as shown:

[tex]5x^{10} y^{13} +3x^{10} y^{13} \\[/tex]

The we add their coefficient together since they have the same incidinal function attached to them i.e [tex]x^{10} y^{13}[/tex]

The sum will give [tex]8x^{10} y^{13}[/tex].

The sum of the equation is [tex]\rm 8 x^{10 }y^{13 }[/tex].

Given that,

Equation; [tex]\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }[/tex]

We have to find,

The sum of the equation.

According to the question,

Equation; [tex]\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }[/tex]

To determine the sum of the equation following all the steps given below.

  • Step1; Convert the numbers 125 and 27 into the cubes,

                    [tex]= \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }\\\\= \sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }[/tex]

  • Step2; Add their coefficient together since they have the same incidental function attached to them,

                   [tex]\rm =\sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }\\\\=5 x^{10 }y^{13 }+ 3 x^{10 }y^{13 }\\\\= 8 x^{10 }y^{13 }\\[/tex]

Hence, The sum of the equation is [tex]\rm 8 x^{10 }y^{13 }[/tex].

For more details refer to the link given below.

https://brainly.com/question/18431073

                   

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