Respuesta :
Answer:
The sum will give [tex]8x^{10} y^{13}[/tex]
Step-by-step explanation:
Given the indicinal equation as shown;
[tex]\sqrt[3]{125}x^{10} y^{13} +\sqrt[3]{27}x^{10} y^{13}[/tex]
To find the sum, we need to find the cube roots of the given number first as shown:
[tex]5x^{10} y^{13} +3x^{10} y^{13} \\[/tex]
The we add their coefficient together since they have the same incidinal function attached to them i.e [tex]x^{10} y^{13}[/tex]
The sum will give [tex]8x^{10} y^{13}[/tex].
The sum of the equation is [tex]\rm 8 x^{10 }y^{13 }[/tex].
Given that,
Equation; [tex]\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }[/tex]
We have to find,
The sum of the equation.
According to the question,
Equation; [tex]\rm \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }[/tex]
To determine the sum of the equation following all the steps given below.
- Step1; Convert the numbers 125 and 27 into the cubes,
[tex]= \sqrt[3]{125} x^{10 }y^{13 }+\sqrt[3]{27} x^{10 }y^{13 }\\\\= \sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }[/tex]
- Step2; Add their coefficient together since they have the same incidental function attached to them,
[tex]\rm =\sqrt[3]{5^3} x^{10 }y^{13 }+\sqrt[3]{3^3} x^{10 }y^{13 }\\\\=5 x^{10 }y^{13 }+ 3 x^{10 }y^{13 }\\\\= 8 x^{10 }y^{13 }\\[/tex]
Hence, The sum of the equation is [tex]\rm 8 x^{10 }y^{13 }[/tex].
For more details refer to the link given below.
https://brainly.com/question/18431073