Question

A mechanic uses a jack to lift up a car. He exerts a force of 11,000 N at a distance of 3m from the axis of rotation. How much torque was put on the car?

Answer 1

Answer:

The amount of torque put on the car is 33,000Nm

Explanation:

Formula for calculating torque is expressed as T = rFsin$\theta$ where;

r is the radius of the  of the arm of the jack = 3m

F is the force exerted = 11000

$\theta$ is the angle of rotation = 90°

On substituting;

$T = 3*11000sin90^{o} \\T = 3*11000 (sin90^{o} =1)\\T = 33000Nm$