Question

You roll a fair number cube. Find each probability:

2. P(2, then 2)

1. P(3, then 5)

3. P(4, then odd)

Answer 1

Answer:

P(2, then 2)  = $\frac{1}{36}$

P(3, then 5) = $\frac{1}{36}$

P(4, then odd) = $\frac{1}{12}$

Step-by-step explanation:

Given: A fair number cube is rolled

To find: P(2, then 2) , P(3, then 5) , P(4, then odd)

Solution:

Probability refers to chances of occurrence of some event.

Probability = Number of favourable outcomes/Total number of outcomes

Sample space = $\left \{ 1,2,3,4,5,6 \right \}$

Total number of outcomes = 6

P(2, then 2)  = P(2)P(2) = $\frac{1}{6}(\frac{1}{6})=\frac{1}{36}$

P(3, then 5) = P(3)P(5) = $\frac{1}{6}(\frac{1}{6})=\frac{1}{36}$

Odd numbers out of the sample space = $\left \{ 1,3,5 \right \}$

P(4, then odd) = P(4)P(odd) = $(\frac{1}{6})(\frac{3}{6} )=\frac{1}{12}$