Answer:
The angle is "27 and 63".
Step-by-step explanation:
Let A and B are two angles, in which A is " [tex]\frac{1}{2}[/tex] " complementary angles and B be is another complementary angle.
Condition of complementary angle :
[tex]A+B =90 ......(i)[/tex]
Solution:
[tex]\ A = \ 3B - 18 \\\\ \ put \ the \ value \ of \ A \ in \ equation.....(i) \\\\ \ Equation: \\ \\\Rightarrow \ A\ +\ B \ =\ 90 \\\\\Rightarrow \ 3B\ -\ 18 \ + \ B \ = \ 90 \\\\\Rightarrow \ 4B \ = \ 90 +18 \\\\\Rightarrow \ 4B = 108 \\\\ \Rightarrow B = \frac{108}{4} \\\\ \Rightarrow B \ = \ 27\\[/tex]
[tex]\ put \ the \ value \ of \ B \ in \ equation (i).\\\\ \ Equation: \\\\\Rightarrow A+B=90\\\\\Rightarrow A+27=90\\\\\Rightarrow A=90-27\\\\\Rightarrow A= 63[/tex]