Answer:
[tex] \sigma^2 = 3^2 \frac{10-1}{10}= 8.10[/tex]
Step-by-step explanation:
For this case we have a sample of n =10 and we have the following statistics:
[tex]\bar X = 37.3 , s= 3[/tex]
And we want to estimate the population variance. We need to remember that the population variance is given by this formula:
[tex]\sigma^2 =\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}[/tex]
And the sample variance is given by:
[tex] s^2 =\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}[/tex]
And we can find a formula for the population variance in terms of the sample deviation like this:
[tex] \sigma^2 = s^2 \frac{n-1}{n}[/tex]
And replacing we got:
[tex] \sigma^2 = 3^2 \frac{10-1}{10}= 8.10[/tex]