Question

A baseball coach graphs some data and finds the line of best fit. The equation for the line of best fit is y=0.32x-20.51,where x is the number of times a bat and y is the number of hits.

How many hits should he expect from a player who is at bat 175 times?

Answer 1

We have been given that a baseball coach graphs some data and finds the line of best fit. The equation for the line of best fit is $y=0.32x-20.51$,where x is the number of times at bat and y is the number of hits.

To find the number of hits in 175 times at bats, we will substitute $x=175$ in our given equation as:

$y=0.32(175)-20.51$

$y=56-20.51$

$y=35.49$

Upon rounding to nearest whole number, we will get:

$y\approx 35$

Therefore, the coach would expect 35 hits from a player who is at bat 175 times.

Answer 2

The expected number of hits  = 35.

The given line of best fit is $y=0.32x-20.51.$

Given that:

x = the number of times a bat = 175.

We have to find y = ?

We plug x = 175 in the given equation.

$y=0.32x-20.51\\y=0.32(175)-20.51\\y=35.49$

The integer before 35.49 is 35. [Because, number of hits can not be fraction.]

So the expected number of hits  = 35.

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