Answer: The gas would occupy volume of 221 ml at STP
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 720 torr
[tex]P_2[/tex] = final pressure of gas = 760 torr (at STP)
[tex]V_1[/tex] = initial volume of gas = 250 ml
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]20^oC=273+20=293K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]273K[/tex] (at STP)
Now put all the given values in the above equation, we get:
[tex]\frac{720\times 250}{293}=\frac{760\times V_2}{273}[/tex]
[tex]V_2=221ml[/tex]
The gas would occupy volume of 221 ml at STP
