What is the sum of the first 9th terms [S(9)]


1
∑ 5( 2n ) = 10+ 5 + ​5/2​ + ​5/4​ + 5⁄8 + ....+ ​5/128 i=-9

Respuesta :

Answer:

[tex]1(2n} = 9 \\1(2 \times 9 = [/tex]

27

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