Question

x^2 - 16x + y^2 - 36=0 what is the center of this circle

Answer 1

Answer:

(8, 18)

Step-by-step explanation:

Complete the square twice:

x^2 - 16x + y^2 - 36 = 0

x^2 - 16x + 8^2 + y^2 - 36 + 18^2 = 0 + 8^2 + 18^2

(x-8)^2 + (y-18)^2 = 388

Center: (8, 18)