Answer:
92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.
(0.46154 , 0.558)
Step-by-step explanation:
Given sample size 'n' = 210
The sample proportion 'p' = 51% = 0.51
Confidence intervals are determined by
[tex](p^{-} - z_{\alpha } \sqrt{\frac{p^{-} (1-p^{-} }{n} } , p^{-} +Z_{\alpha } \sqrt{\frac{p^{-} (1-p^{-} )}{n } } )[/tex]
The 92% of z-score value
[tex]Z_{\frac{\alpha }{2} } = Z_{\frac{0.08}{2} } = Z_{0.04} = 1.405[/tex]
92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.
[tex](0.51 - 1.405 \sqrt{\frac{0.51 (1-0.51 }{210} } , 0.51 +1.405 \sqrt{\frac{0.51 (1-0.51)}{210 } } )[/tex]
on calculation , we get
(0.51-0.048 , 0.51 + 0.048)
(0.46154 , 0.558)
Final answer:-
92% Of confidence intervals to estimate the proportion of all fast-growing small companies that have a management succession plan.
(0.46154 , 0.558)