The area of the regular hexagon with radius length 4 m will be 24√3 square meters.
The polygon which is having six sides and each side are congruent. And each internal angle of the hexagon will be of 120 degrees.
The area of the regular hexagon is six times area of the equilateral triangle.
Area of regular hexagon = 6 x Area of the equilateral triangle.
The regular hexagon with radius length 4 m.
The area of the equilateral triangle will be
Area = (√3 / 4) x (side)²
Area = (√3 / 4) x 4²
Area = 4√3 square meters
Then the area of the regular hexagon with radius length 4 m will be
Area of regular hexagon = 6 x 4√3
Area of regular hexagon = 24√3 square meters
The area of the regular hexagon with radius length 4 m will be 24√3 square meters.
The diagram is attached below.
More about the regular hexagon link is given below.
https://brainly.com/question/1694257
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