Answer:
total paper required = 57 cm²
Step-by-step explanation:
given data
slant height b = 4 cm
base side h = 3 cm
block height h1 = 2 cm
solution
we get surface area of right squared pyramid by add here areas of all 4 triangles that is express as
area = 4 × Area of Triangles
area = 4 × [tex]\frac{bh}{2}[/tex]
area = 4 × [tex]\frac{4\times 3}{2}[/tex]
area = 24 cm²
and
surface are of the box is equal to the area of its 4 side faces + base
area = 4 × ( h × h1 ) + h²
area = 4 × ( 3 × 2 ) + 3²
area = 24 + 9
area = 33 cm²
so total paper required = 24 + 33
so total paper required = 57 cm²