Question

Can someone help and answer this problem please!

Answer 1

Answer:

C.) $\frac{a^6}{b^5}$

Step-by-step explanation:

$\frac{a^2b^{-7}}{a^{-4}b^{-2}}$

Use the quotient rule $\frac{x^a}{x^b}=x^{a-b}$ :

$a^{2+4}b^{-7+2}\\\\a^6b^{-5}$

Use the negative power rule $x^{-a}=\frac{1}{x^a}$ :

$a^6*\frac{1}{b^5}\\\\\frac{a^6*1}{b^5}\\ \\\frac{a^6}{b^5}$

:Done

Answer 2

Answer:

D

Step-by-step explanation:

$\dfrac{a^2b^{-7}}{a^{-4}a^{-2}}=\\\dfrac{a^2}{a^{-4}}\cdot \dfrac{b^{-7}}{b^{-2}}=$

$a^6b^{-5}$, or option D. Hope this helps!