Complete question:
Jason has two bags with 6 tiles each. The tiles in each bag are shown below:
1 2 3 4 5 6
Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered three from the second bag?
Answer: 1/36
Step-by-step explanation:
Number of tiles in each bag = 6
Probability of drawing tile numbered 2 from the first bag and the tile numbered 3 from the second
Probability of drawing number 2 from first bag :
P(numbered 2) = (required outcome / possible outcome)
P(numbered 2) = 1/6
Probability of drawing number 2 from first bag :
P(numbered 3) = 1/6
Since they are independent events :
P(drawing 2 from bag one and 3 from bag 2) :
1/6 × 1/6 = 1/36
