Question

The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm^3 of water.
Find the percent of the cup that is filled with water after 3 seconds.

Answer 1

Answer:

About 90%

Step-by-step explanation:

If the cup was filled at a constant rate, then the cup fills at 70/2=35 cubic centimeters per second. The formula for the volume of a cone is $\frac{1}{3} \pi r^2 h$, or in this case $\frac{112}{3}\pi$ cubic centimeters. After 3 seconds, the cup would have 35*3=105 cubic centimeters of water inside of it, or about 89.52% which rounds to 90%. Hope this helps!