Question

The Figure below shows a triangle with vertices a and B on a circle and vertex C outside it Side AC is tangent to the circle side BC is a sink and intersecting the circle at point X what is the measure of angle ACB

32
6
24
12

Answer 1

Answer:

the answer is 12 degrees

Answer 2

The measure of angle ACB when the secant BC and the tangent AC intersect is 12°

Secant and Tangent intersection

When a secant and a tangent meet outside the circle, thwe product of the length of the secant and its external segment equals the square of the length of the tangent segment.

Therefore,

arc XA = 2(64) = 128 degrees.

Hence,

m∠C = 1 / 2 (152 - 128)

m∠C = 1 / 2 (24)

m∠ACB = 12°

Therefore, angle ACB is 12 degrees.

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