Answer:
[tex]68\%[/tex]
Step-by-step explanation:
Let A be the event that Daniel receives call from SeaWorld.
Probability of event A, P(A) = [tex]35\%[/tex]
Let B be the event that Daniel receives call from Central Park Zoo.
Probability of event B, P(B) = [tex]48\%[/tex]
Probability that Daniel receives calls from both SeaWorld and Central Park Zoo:
[tex]P(A \cap B) = 15\%[/tex]
We know that formula:
Probability that Daniel receives call from either SeaWorld or Central Park Zoo but not both:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)\\\Rightarrow P(A \cup B) = 35\% + 48\% - 15\%\\\Rightarrow P(A \cup B) = 68\%[/tex]
Hence, required probability is [tex]68\%[/tex].