Question

Calculate the concentration in M) of hydroxide ions in a solution with a pOH of 2.468
A) 2.94 x 102
B) 3.40 x 1011
OC) 3.40 x 10-3
OD) 2.94 x 10-12​

Answer 1

Answer:

C) 3.40 x 10-3

Explanation:

Hello,

In this case, for the given pOH, we are able to compute the concentration of hydrixide ions by applying the following formula:

$pOH=-log([OH^-])$

$[OH^-]=10^{-pOH}=10^{-2.468}$

$[OH^-]=0.0034M=3.4x10^{-3}M$

Therefore, answer is C).

Best regards.

Answer 2

Answer:

3.40 × 10⁻³ M

Explanation:

The pOH scale is used to express the acidity or basicity of a solution.

• If pOH < 7, the solution is basic.
• If pOH = 7, the solution is neutral.
• If pOH > 7, the solution is acid.

The pOH of this solution is 2.468, so it is basic. We can calculate the concentration of hydroxide ions in the solution using the following expression.

$pOH = -log [OH^{-} ]\\\[[OH^{-}] = antilog-pOH = antilog-2.468 = 3.40 \times 10^{-3} M$