Answer:
Actual dimension of the field = 42 ft × 21 ft
Equation : [tex]y=\frac{7}{2}x[/tex]
Step-by-step explanation:
Scale for the drawing of a rectangular playing field is,
2 inches = 7 feet
Or 1 inch = 3.5 feet
If length of the playing field on drawing = 12 in
Then actual length of the field = 12×3.5 = 42 feet
And width on the drawing = 6 inches
Therefore, actual width of the field = 6×3.5 = 21 feet
If 'x' is the dimension of a scale drawing and 'y' be the corresponding dimension of the actual field,
[tex]\frac{x}{y}=\frac{2}{7}[/tex]
[tex]y=\frac{7}{2}x[/tex]