Question

What is the greatest prime factor of [4²]² -1?

Answer 1

Using the formula

$a^2-b^2=(a+b)(a-b)$

We can write

$(4^2)^2-1 = 16^2-1 = (16+1)(16-1)=17\cdot 15$

Since 17 is prime and the factors of 15 are 3 and 5, the three prime factors of this number are 3, 5 and 17.

Answer 2

Answer:{Redacted)

Step-by-step explanation:{Redacted}

Used the wrong formula.

Wish there was a delete option...