Respuesta :

Using the formula

[tex]a^2-b^2=(a+b)(a-b)[/tex]

We can write

[tex](4^2)^2-1 = 16^2-1 = (16+1)(16-1)=17\cdot 15[/tex]

Since 17 is prime and the factors of 15 are 3 and 5, the three prime factors of this number are 3, 5 and 17.

Answer:{Redacted)

Step-by-step explanation:{Redacted}

Used the wrong formula.

Wish there was a delete option...

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