Answer:
Perimeter is 38.8 units and approximately 39 units
Step-by-step explanation:
Given: Graph
To find: perimeter of the polygon
Solution:
Distance between points [tex](x_1,y_1),(x_2,y_2)[/tex] is given by [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
As per the graph,
point P is (-2,11)
point Q is (-4,6)
point R is (2,0)
point S is (1,7)
point T is (8,7)
[tex]PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units[/tex]
Perimeter refers to sum of lengths of all the sides.
Perimeter = [tex]5.4+8.5+7.1+7+10.8=38.8[/tex]
Or approximately 39 units
