Question

Find the equation of the circle with center at (3,-2) and radius of 3.
(x - 3)2 + (y + 2)2 = 9
(x - 3)2 + ( + 2)2 = 3
b. (X + 3)2 + (-2)2 = 9
d. (x+ 3)+ (x - 2)2 = 3

Answer 1

Answer:

$(x - 3)^2 + (y + 2)^2 = 9$

Step-by-step explanation:

$(x - x1)^2 + (y - y2)^2 = r^2$

Now that you know the formula, you can just add in the numbers from your coordinate point and radius with their respective signs.

$(x - 3)^2 + (y + 2)^2 = 9$