Question

A force of 310.0 N is used to push a 120 kg 30.0 m horizontally 3.00 s.
(a) Calculate the work done on the mass.
[ ] × kJ
(b) Calculate the power developed.
[ ] kW​

Answer 1

Explanation:

We have,

Force acting on the mass is 310 N

Mass, m = 120 kg

Distance covered by the mass is 30 m

Time, t = 3 s

(a) The work done on the mass is given by the product of force and displacement such that,

$W=Fd\\\\W=310\times 30\\\\W=9300\ J$

(b) The rate at which the work is done is called power developed. Its formula is given by :

$P=\dfrac{W}{t}\\\\P=\dfrac{9300}{3}\\\\P=3100\ W$