Question

A 56.8g sample of aluminum is heated from 79.5°C to 143.7°C. The specific heat capacity of aluminum is 0.900 J/(g*K). Calculate the heat absorbed.
A) 3280 J
B) 4440 J
C) 6220 J
D) 11400 J

Answer 1

Answer:

I think the answer is A.

Answer 2

The heat absorbed should be option A. 3,280 J.

Calculation of the heat absorbed:

Since A 56.8g sample of aluminum is heated from 79.5°C to 143.7°C. The specific heat capacity of aluminum is 0.900 J/(g*K).

So based on this, the following formula should be applied

= Mass of substance * specific heat * change in temperature

= 56.8 * 0.900 J * (143.7 - 79.5)

= 56.8 * 0.900 J * 64.2

= 3,280 J

hence, the first option is correct.

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