Question

7. What is the temperature in degrees C when .500 moles of gas occupying 1
9.00 liters exert a pressure of 200.0 kPa?

answer choices

433 C
160. C
.00231 C

Answer 1

Answer:

433C

Explanation:

PV=Nrt

step 1. convert 200 kpa to atm

step 2. write equation

1.97385atm*9L=.500mol*.0821*T

17.76465=.04105*T

17.76465/.04105

432.756394641C

step 3. round

433C