Question

4) A patient on a low-salt diet is limited to 1500 mg of sodium (Na) per day. A box
of crackers shows 0.320 gram of Na per cracker. How many crackers can the
patient eat without exceeding her daily limit of Na?

Answer 1

Answer:

4687 crackers

Step-by-step explanation:

1500/0.320 = 4687.5

Therefore 4688 crackers would exceed so the patients can only have 4687

I hope this is helpful!!! :)

Answer 2

Inequalities help us to compare two unequal expressions. The maximum number of crackers that the patient can take is 4.

What are inequalities?

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

Let the number of crackers that the patient has be represented by x.

As it is given that the content of sodium in a cracker is 0.320 grams, if converted to milligrams, it will be 320 grams. Also, it is given that the amount of sodium that is allowed to the patient is 1500 milligrams. Therefore, the inequality can be written as,

$320x\leq 1500\\\\x \leq \dfrac{1500}{320}\\\\x\leq 4.6875$

Therefore, the maximum number of crackers that the patient can take is 4.

Learn more about Inequality:

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