Question

WILL GIVE BRAINLIEST
Ricky has a bowl with 80 jelly beans in it there are 16 red, 24 green 12 yellow, 20 orange, and 8 black jelly beans ricky takes one jellybean from the bowl without looking what is the possibility that it is a yellow jellybean

Answer 1

Answer:

Probability = number of yellow jellybeans / total number of jellybeans

=  24 / 80

=  3/10.

Step-by-step explanation:

Answer 2

Answer:

15%

Step-by-step explanation:

There are 80 total jelly beans, as stated in the question. Therefore, there are 80 "Total Events".

There are 12 yellow jellybeans in the bowl. Therefore, there are 12 preferred events, since the question asks the probability of pulling one yellow jellybean randomly.

$\frac{\text{Preferred Events}}{\text {Total Events}} =\frac{12}{80}$

I do not know what form the question prefers, so I did the probability in all forms.

Probability as a decimal:

Divide 12 by 80.

$12/80 = 0.15$

There is a 0.15 chance that Ricky would pull out a yellow bean.

Probability as a Percent:

Divide 12 by 80.

$12/80=0.15$

Convert into a percent. Multiply 0.15 by 100.

$0.15*100=15$

There is a 15% chance that Ricky would pull out a yellow bean.

Probability as a Fraction:

Simplify 12/80.

$\frac{12/2}{80/2} =\frac{6/2}{40/2} =\frac{3}{20}$

There is a $\frac{3}{20}$ chance that Ricky would pull out a yellow bean.

Brainilest Appreciated!