Answer:
1. [tex]\frac{1}{4}[/tex]
2. 3 yards
3. [tex]8 \frac{3}{4}[/tex] laps
4. 2.5 pounds
5. [tex]\frac{5}{8}[/tex] pounds
Step-by-step explanation:
1.
[tex]\frac{1}{3}[/tex]×[tex]\frac{3}{4} =\frac{3}{12} =\frac{1}{4}[/tex]
2.
[tex]4- 1 \frac{3}{5} - 2 \frac{1}{3} = \frac{60}{15} - \frac{24}{15} - \frac{35}{15} = \frac{15}{15} = 1[/tex]
So he must've used 3 yards if there is 1 yard remaining.
3.
7÷[tex]\frac{4}{5}[/tex]=7×[tex]\frac{5}{4} =\frac{35}{4} = 8 \frac{3}{4}[/tex]
4.
10.5-(3×2.5)-(2×0.25)=
10.5-7.5-0.5=
10.5-8=
2.5
His emptied backpack weighs 2.5 pounds.
5.
[tex]1 \frac{1}{4} - \frac{5}{8} = \frac{5}{4} -\frac{5}{8} = \frac{10}8} -\frac{5}{8} = \frac{5}{8}[/tex]
The large package is [tex]\frac{5}{8}[/tex] pounds heavier than the smaller one.
