The oxidation number of chromium in the chromate ion, CrO4²- is +6. Details about oxidation number can be found below.
Oxidation number refers to the hypothetical charge of an atom within a molecule.
According to this question, a chromate ion was given as follows: CrO4²-
The oxidation number of oxygen is -2, hence, the oxidation number of chromium can be calculated as follows:
x - 2(4) = -2
x - 8 = -2
x = -2 + 8
x = 6
Therefore, the oxidation number of chromium in the chromate ion, CrO4²- is +6.
Learn more about oxidation number at: https://brainly.com/question/15167411
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