Question

How many moles of oxygen are required to react completely with 16.5 mol Al?

Answer 1

Answer:

12.4 mol O2

Explanation:

                                4Al +       3O2 -----> 2Al2O3

from reaction          4 mol        3 mol

given                    16.5 mol       x mol

x = 16.5*3/4 =12.4 mol    O2