Question

22 John's father is 5 times older than john and John is twice as his sister Alice. In two years to time sum
of their age will be 58. What is their present age​

Answer 1

Answer:

Alice-4

John-8

Dad-40

Step-by-step explanation:

1) using the information we know if j is John's age and a is Alice's age and d if dad's age:

2a=j

d=5j=5(2a)=10a

(a+2)+(d+2)+(j+2)=58

2) substitute the d and j for the equivalent terms using a so there is only one variable, Alice's age:

(a+2)+(10+2)+(2a+2)=58

3) combine like terms and isolate the variable and you should get your answer.