Answer:
The correct option is;
D. 30 and 40
Step-by-step explanation:
Here, we have that the rhombus is a quadrilateral with equal and parallel sides hence the length of the diagonals will be
2 × 25×sinθ and 2 × 25× cosθ
Therefore tanθ = (2 × 25×sinθ)/(2 × 25× cosθ) = (sinθ)/(cosθ)
Therefore, the root of the sum squares of both diagonals = 50
Therefore, we analyze each of the options as follows
For A. we have √(22² + 40²) = 45.65 ≠ 50 therefore these are not the length of diagonals of the rhombus in question
For B. we have √(26² + 36²) = 44.41 ≠ 50 therefore these are not the length of diagonals of the rhombus in question
For C. we have √(26² + 48²) = 55.59 ≠ 50 therefore these are not the length of diagonals of the rhombus in question
For D. we have √(30² + 40²) = 50 therefore these are possible lengths of diagonals of the rhombus in question.
