Answer:
10
Step-by-step explanation:
We cannot use the Pythagorean Theorem here because we only have one side length. However, we can use the fact that [tex]\frac{a}{sin(A)} =\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]
I decided to make the corner with the 60° as ∠A, the corner with the 30° as ∠B, and the corner with the right angle as ∠C. While then making side a as the unmarked side, side b as the side with 5, and the hypotenuse p as side c.
Since we do not need to solve for a in this equation to solve for p, we can simply use the sides and numbers we are given.
Manipulating two of our equations, preferably the equations with the variables b and c, we can get [tex]\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex] and solving for c, which is p in this case, will give us [tex]c=\frac{bsin(C)}{sin(B)}[/tex]
Plugging in the numbers we have gives us [tex]c=\frac{5sin(90)}{sin(30)}[/tex] = 10 mi
