Question

13POINTS!!!

In ΔWXY, y = 4.5 cm, w = 5.7 cm and ∠X=155°. Find the length of x, to the nearest 10th of a centimeter.

Answer 1

Using cosine rule,
x^2=y^2+w^2-(2yw x cos X)
x^2=4.5^2+5.7^2-(2x4.5x5.7xcos 155)
x^2=99.2336
x=root over 99.2336
x=9.96 cm.
I hope this helps!

Answer 2

Answer:10

Step-by-step explanation: deltamath